A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?
Chemistry
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Question
A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?
2 Answer

1. User Answers Larus
On the basis of the given data:
Volume (V) is 37.5 L
Temperature (T) is 307 K
Pressure (P) is 1.25 atm
In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K
n = PV / RT
n = 1.25 atm × 37.5 L / 0.0821 Latm/mol/K × 307 K
n = 1.85 mol

2. User Answers yessssssvdfbfdbf
Answer:
1.86
Explanation: