Chemistry

Question

A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?

2 Answer

  • On the basis of the given data:

    Volume (V) is 37.5 L

    Temperature (T) is 307 K

    Pressure (P) is 1.25 atm

    In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K

    n = PV / RT

    n = 1.25 atm × 37.5 L / 0.0821 Latm/mol/K × 307 K

    n = 1.85 mol

  • Answer:

    1.86

    Explanation:

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