Chemistry

Question

A container of carbon dioxide gas at a pressure of 325 kPa and a temperature of -5.20 °C has a fixed volume. What is the pressure inside the container after it warms to 22.5 °C?

1 Answer

  • Answer:

    359 kPa

    Explanation:

    Volume remains constant, so we can use Gay-Lussac’s Law.

    p₁/T₁ = p₂/T₂     Multiply both sides by T₂  

      p₂ = p₁ × T₂/T₁

    Data:

    p₁ = 325 kPa; T₁ = -5.20°C

    p₂ = ?;            T₂ = 22.5°C

    Calculations:

    (a) Convert the temperatures to kelvins

    T₁ = -5.20 + 273.15

    T₁ = 267.95 K

    T₂ = 22.5 + 273.15

    T₂ = 295.65 K

    (b) Calculate the new pressure

    p₂ = 325 × 295.65/267.95

    p₂ = 325 × 1.105

    p₂ = 359 kPa

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