Mathematics

Question

Solve the following systems of equations:
4x+5y=-4
4x+3y=12

X=?
Y=?

2 Answer

  • For this case we have the following system of equations:

    [tex]4x + 5y = -4\\4x + 3y = 12[/tex]

    We multiply the second equation by -1:

    [tex]-4x-3y = -12[/tex]

    We add the equations:

    [tex]4x-4x + 5y-3y = -4-12\\5y-3y = -4-12\\2y = -16\\y = \frac {-16} {2}\\y = -8[/tex]

    We find the value of "x":

    [tex]4x = 12-3y\\x = \frac {12-3y} {4}\\x = \frac {12-3 (-8)} {4}\\x = \frac {12 + 24} {4}\\x = \frac {36} {4}\\x = 9[/tex]

    Thus, the solution of the system is given by:

    [tex](x, y) :( 9, -8)[/tex]

    ANswer:

    (9, -8)

  • Answer:

    x = 9 and y = -8

    Step-by-step explanation:

    It is given that,

    4x + 5y = -4     ----(1)

    4x + 3y = 12    -----(2)

    To find the value of x and y

    eq (1) - eq (2) ⇒

    4x + 5y = -4     ----(1)

    4x + 3y = 12    -----(2)

      0 + 2y = -16

    y = -16/2 = -8

    Substitute the value of y in eq (1)

    4x + 5y = -4     ----(1)

    4x + 5*-8 = -4

    4x - 40 = -4

    4x = -4 + 40 = 36

    x = 36/4 = 9

    x = 9 and y = -8

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