Solve the following systems of equations: 4x+5y=4 4x+3y=12 X=? Y=?
Question
4x+5y=4
4x+3y=12
X=?
Y=?
2 Answer

1. User Answers carlosego
For this case we have the following system of equations:
[tex]4x + 5y = 4\\4x + 3y = 12[/tex]
We multiply the second equation by 1:
[tex]4x3y = 12[/tex]
We add the equations:
[tex]4x4x + 5y3y = 412\\5y3y = 412\\2y = 16\\y = \frac {16} {2}\\y = 8[/tex]
We find the value of "x":
[tex]4x = 123y\\x = \frac {123y} {4}\\x = \frac {123 (8)} {4}\\x = \frac {12 + 24} {4}\\x = \frac {36} {4}\\x = 9[/tex]
Thus, the solution of the system is given by:
[tex](x, y) :( 9, 8)[/tex]
ANswer:
(9, 8)

2. User Answers imlittlestar
Answer:
x = 9 and y = 8
Stepbystep explanation:
It is given that,
4x + 5y = 4 (1)
4x + 3y = 12 (2)
To find the value of x and y
eq (1)  eq (2) ⇒
4x + 5y = 4 (1)
4x + 3y = 12 (2)
0 + 2y = 16
y = 16/2 = 8
Substitute the value of y in eq (1)
4x + 5y = 4 (1)
4x + 5*8 = 4
4x  40 = 4
4x = 4 + 40 = 36
x = 36/4 = 9
x = 9 and y = 8