Mathematics

Question

Solve the following system of equations:
-8x+3y=7
13-3y=-17

X=?
Y=?

2 Answer

  • Answer:

    x = -2 and y = -3

    Step-by-step explanation:

    It is given that,

    -8x + 3y =7    ----(1)

    13x - 3y =-17   -----(2)

    To find the value of x and y

    eq(1) + eq(2) ⇒

    -8x + 3y = 7    ----(1)

    13x -  3y = -17   -----(2)

     5x +    = -10

    x = -10/5 = -2

    Substitute value of x in eq (1)

    -8x + 3y =7    ----(1)

    -8 * -2  + 3y = 7

    16 + 3y = 7

    3y = 7 - 16 = -9

    y = -9/3 = -3

    Therefore x = -2 and y = -3

  • For this case we must solve the following system of equations:

    [tex]-8x + 3y = 7\\13x-3y = -17[/tex]

    If we add both equations we have:

    [tex]-8x + 13x + 3y-3y = 7-17\\5x = -10\\x = \frac {-10} {5}\\x = -2[/tex]

    We find the value of the variable "y":

    [tex]3y = 7 + 8x\\y = \frac {7 + 8x} {3}\\y = \frac {7 + 8 (-2)} {3}\\y = \frac {7-16} {3}\\y = \frac {-9} {3}\\y = -3[/tex]

    Thus, the solution of the system is (-2, -3)

    ANswer:

    (-2, -3)

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