Mathematics

Question

What is the value of -6x3-y2-3xy if x=-2 and y=4

2 Answer

  • Hello!

    The answer is:

    The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

    Why?

    To solve the problem, we need to evaluate both variables for the given values:

    [tex]x=-2[/tex]

    and

    [tex]y=4[/tex]

    So, we are given the expression:

    [tex]-6x^{3}-y^{2}-3xy[/tex]

    Then, evaluating the given values for both variables, we have:

    [tex]-6*(-2)^{3}-(4)^{2}-3*(-2)*(4)=(-6*-8)-(16)+24=48-16+24=56[/tex]

    Hence, we have that the answer is:

    The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

    Have a nice day!

  • Answer:

    The value of given expression = 56

    Step-by-step explanation:

    It is given an expression in variable x and y

    -6x³ - y² - 3xy

    To find the value of given expression

    Let expression be,

    -6x³ - y² - 3xy

    When x = -2 and y =4

    -6x³ - y² - 3xy = -6(-2)³ - 4² - (3 * -2 * 4)

     = -6*-8 - 16 + 24

     = 48 - 16 + 24

     = 56

    Therefore the value of given expression is 56

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