Mathematics

Question

1. Solve for x:
3(2x – 1) – 10 = 8 + 5x
A. -7
B. -3
C. 19
D. 21

2 Answer

  • Answer:

    (D) 21

    Explanation:

    3(2x−1)−10=8+5x

    Step 1: Simplify both sides of the equation.

    3(2x−1)−10=8+5x

    (3)(2x)+(3)(−1)+−10=8+5x(Distribute)

    6x+−3+−10=8+5x

    (6x)+(−3+−10)=5x+8(Combine Like Terms)

    6x+−13=5x+8

    6x−13=5x+8

    Step 2: Subtract 5x from both sides.

    6x−13−5x=5x+8−5x

    x−13=8

    Step 3: Add 13 to both sides.

    x−13+13=8+13

    x=21

  • Answer:

    D. 21

    Step-by-step explanation:

    Given equation: [tex]\[3(2x – 1) – 10 = 8 + 5x\] [/tex]

    Simplifying:

    [tex]\[6x – 3 – 10 = 8 + 5x\] [/tex]

    => [tex]\[6x – 13 = 8 + 5x\] [/tex]

    => [tex]\[6x – 5x = 8 + 13\] [/tex]

    => [tex]\[(6 – 5)x = 21\] [/tex]

    => [tex]\[x = 21\] [/tex]

    Verifying by substituting the value of x in the equation:

    Left Hand Side: [tex]\[3(2x – 1) – 10\][/tex]

    [tex]\[3(2*21 – 1) – 10\][/tex]

    = [tex]\[3(42 – 1) – 10\][/tex]

    = [tex]\[3(41) – 10\][/tex]

    = [tex]\[123 – 10\][/tex]

    = [tex]\[113\][/tex]

    Right Hand Side: [tex]\[8 + 5x\][/tex]

    = [tex]\[8 + 5*21\][/tex]

    = [tex]\[8 + 105\][/tex]

    = [tex]\[113\][/tex]

    So, Left Hand Side = Right Hand Side when x=21.

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