Consider the graph of the line y = .5x 4 and the point (4,2). The slope of a line parallel to the given line is (1/ 24 A point on the line parallel to the giv
Question
(4,2).
The slope of a line parallel to the given line is
(1/
24
A point on the line parallel to the given line, passing
through (4, 2), is (0,4) 4.
The slope of a line perpendicular to the given line is
2
A point on the line perpendicular to the given line,
passing through (4,2), is
2 Answer

1. User Answers power5
Answer:
slope of parallel line and perpendicular line are 5 and 1/5 espectively
equation of parallel and perpendicular line are y = 5x + 22 [tex]y= \frac{1}{5} x+\frac{6}{5}[/tex] respectively
Stepbystep explanation:
y = 5x  4 is in the form
y = mx + c
where m is the slope of the line and c is the y intercept of thr line
therefore slope of the line = 5 and y intercept = 4
when an another line is parallel to the given line then the slope of both the lines are equal
therefore the slope the parallel line = 5
equation of a line passing through a given point [tex](x_{1} ,y_{1})[/tex] with slope m is given by [tex]yy_{1} = m(xx_{1} )[/tex]
given [tex](x_{1} ,y_{1})[/tex]= (4,2)
therefore equation of line y2 = 5(x+4)
therefore y = 2+ 5x+20
y = 5x + 22is the eqaution of required line.
when two lines are perpendiculer then
[tex]m_{1} m_{2}=1[/tex]
where [tex]m_{1} and m_{2}[/tex] are slope of the lines therefore
m×5=1
therefore m= [tex]\frac{1}{5}[/tex]
therefore eqaution of line passing through (4,2) and with slope m= [tex]\frac{1}{5}[/tex] is given by [tex]y  2= \frac{1}{5} (x+4)[/tex]
[tex]y= \frac{1}{5} x+\frac{6}{5}[/tex]

2. User Answers haleycaraway2
Answer:
1/2
(0,4)
2
(2,2)
Stepbystep explanation:
edge