Mathematics

Question

Graph the linear equation find three points that solves the equation 2y=5x+11

1 Answer

  • Answer:

    Attachment

    Step-by-step explanation:

    Convert to the slope-intercept form (y = mx + b):

    [tex]2y=5x+11[/tex]             divide both sides by 2

    [tex]\dfrac{2y}{2}=\dfrac{5x}{2}+\dfrac{11}{2}\\\\y=\dfrac{5}{2}x+\dfrac{11}{2}[/tex]

    We choose any three x values ​​and calculate the y value:

    for x = -1

    [tex]y=\dfrac{5}{2}(-1)+\dfrac{11}{2}=-\dfrac{5}{2}+\dfrac{11}{2}=\dfrac{6}{2}=3\to A(-1,\ 3)[/tex]

    for x = 1

    [tex]y=\dfrac{5}{2}(1)+\dfrac{11}{2}=\dfrac{5}{2}+\dfrac{11}{2}=\dfrac{16}{2}=8\to B(1,\ 8)[/tex]

    for x = -3

    [tex]y=\dfrac{5}{2}(-3)+\dfrac{11}{2}=-\dfrac{15}{2}+\dfrac{11}{2}=-\dfrac{4}{2}=-2\to C(-3,\ -2)[/tex]

    Mark the points on the coordinate plane and draw a line through the given points.

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