Mathematics

Question

Struggling un this section
Struggling un this section

1 Answer

  • Answer:

    [tex]10[/tex]

    Step-by-step explanation:

    Combinations : When there are total [tex]n[/tex] choices and you have to choose [tex]k[/tex]of them (in any order)

                     The possible ways [tex]= \ ^n{c_{k}} = \frac{n!}{k!(n-k)!}[/tex]

    Here total chances [tex]=5[/tex]

    and we have to choose [tex]2[/tex]of them.

    Possible ways[tex]=\ ^5{c_{2}}[/tex]

                                 [tex]=&\frac{5!}{2!(5-2)!} = \frac{5!}{3! 2!} \\\\=&\frac{5 \times 4\times 3!}{3! 2!} = \frac{5 \times 4}{2} = 10[/tex]

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