Caterer A charges $15 per person and $100 to set up tables. Caterer B charges $20 per person and $50 to set up tables. Graph a system of equations. For what num
Question
2 Answer

1. User Answers stephmruk
Answer: 10 guests, $250
Stepbystep explanation:
Use the equation y=mx+b
Plug in what you are given.
For caterer A the cost per guest is $15. This is the m value. The b value is the additional fee for setting up the tables, $100. Your equation should be y=15x+100.
Caterer B charges $20 per guest and a $50 fee to set up tables. The equation will be y=20x+50.
To find the number of guests that will result in an equal cost, set the equations equal to one another. Solve for x.
15x+100=20x+50
Do this by getting the x’s all on one side (I subtracted 15x on both sides). Then subtract the 50 from both sides. This results in the equation 50=5x. Dividing by 5 will make x equal to 10.
To find the cost at this number of guests plug 10 into either equation y=15x+100 or y=20x+50. This results in a cost of $250.

2. User Answers 1Nezukochannnn1
Answer: 10 guests, $250
Stepbystep explanation:
Use the equation y=mx+b
Plug in what you are given.
For caterer A the cost per guest is $15. This is the m value. The b value is the additional fee for setting up the tables, $100. Your equation should be y=15x+100.
Caterer B charges $20 per guest and a $50 fee to set up tables. The equation will be y=20x+50.
To find the number of guests that will result in an equal cost, set the equations equal to one another. Solve for x.
15x+100=20x+50
Do this by getting the x’s all on one side (I subtracted 15x on both sides). Then subtract the 50 from both sides. This results in the equation 50=5x. Dividing by 5 will make x equal to 10.
To find the cost at this number of guests plug 10 into either equation y=15x+100 or y=20x+50. This results in a cost of $250. 
 totally didn't copy this from a site