A 2 kg soccer ball is traveling 28.62m/s when it hits the wall and bounces off of the wall with a velocity of 20 m/s. If the wall exerted an average force of 65
Physics
KingDallydaz9901
Question
A 2 kg soccer ball is traveling 28.62m/s when it hits the wall and bounces off of the wall with a velocity of 20 m/s. If the wall exerted an average force of 652.36N on the ball, how long was the ball in contact with the wall?
1 Answer

1. User Answers Pharero
Answer:
0.149 s or 0.15 s
Explanation:
let initially ball is moving towards left hence initial velocity =  28.62 m/s
final velocity as ball moves right = +20 m/s
force = rate of change in momentum
force = mass × change in velocity / time
or time = mass × change in velocity / force
time = 2× ( 20 ( 28.62)) / 652.36
time = 2× ( 20 +28.62)) / 652.36
time = 2× 48 .62/652.36
time = 0.149 s or 0.15 s