Iridium192 is an isotope of iridium and has a half life of 73.83 days. If a laboratory experiment begins with 100 grams of iridium192, the number of grams, A,
Question
2 Answer

1. User Answers freckledspots
Answer:
[tex]A=100(0.990655512)^t[/tex]
Stepbystep explanation:
[tex]A=100(\frac{1}{2})^{\frac{t}{73.83}}[/tex]
It does say an approximate equation so we could play with law of exponents a little especially if you don't like that fraction in the exponent.
[tex]A=100(\frac{1}{2})^{\frac{1 \cdot t}{73.83}}[/tex]
[tex]A=100(\frac{1}{2})^{\frac{1}{73.83}t}[/tex]
[tex]A=100((\frac{1}{2})^{\frac{1}{73.83}})^t[/tex]
I'm going to put (1/2)^(1/73.83) into my calculator.
This gives me approximately: 0.990655512.
[tex]A=100(0.990655512)^t[/tex]
So maybe that is what you are looking for.
Please let me know.

2. User Answers jainveenamrata
A gram of the isotope of iridium is present. Then after t day, the equation is [tex]\rm A = 100*(0.990655)^t[/tex].
What is halflife?
HalfLife is defined as the time required by a radioactive substance to disintegrate into a different substance. This was discovered in 1907 by Ernest Rutherford.
Given
Iridium192 is an isotope of iridium and has a halflife of 73.83 days.
[tex]\rm A= 100(0.5)^\frac{t}{73.83}[/tex]
If A gram of the isotope of iridium is present. Then after t day, the amount will be
[tex]\rm A= 100(0.5)^{\frac{t}{73.83}}\\[/tex]
On simplifying, we have
[tex]\rm A = 100((0.5)^{\frac{1}{73.83}})^{t} \\\\A = 100*(0.990655)^t[/tex]
Thus, the required equation is [tex]\rm A = 100*(0.990655)^t[/tex].
More about the halflife link is given below.
https://brainly.com/question/24710827