Mathematics

Question

What is the average rate of change of the function on the interval from x = 0 to x = 5?


f(x)=

1/2^(3)x

1 Answer

  • Answer:

    Average rate of change [tex]=\frac{1}{8}[/tex]

    Step-by-step explanation:

    Given interval are from [tex]x=0\ to\ x=5[/tex]

    Also,[tex]=\frac{1}{2^3}x=\frac{1}{8}x[/tex]

    Average rate of change[tex]=\frac{f(b)-f(a)}{b-a}\ for\ given\ interval\ [a,b][/tex]

    Here given intervals are [tex]a=0\ and\ b=5[/tex]

    Plugging these value in formula, we get.

    Average rate of change[tex]=\frac{\frac{1}{8}(5)-\frac{1}{8}(0)}{5-0}\\\\=\frac{\frac{1}{8}(5)-0}{5-0}\\ \\=\frac{\frac{1}{8}(5)}{5}\\\\=\frac{1}{8}[/tex]

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