What is an equation of the line that passes through the point (2, 1) and is parallel to the line whose equation is 4x2y=8?
Question
2 Answer

1. User Answers Yang100
Answer:
y1=2(x+2)
Stepbystep explanation:
4x2y=8
2y=4x8
y=4/2x8/2
y=2x4

Parallel means same slope.
m=2
yy1=m(xx1)
y1=2(x(2))
y1=2(x+2)

2. User Answers MrRoyal
Parallel lines have the same slope
The equation of the line is: [tex]y = 2x+5[/tex]
The equation is given as:
[tex]4x  2y =8[/tex]
Divide through by 2
[tex]2x  y =4[/tex]
Make y the subject
[tex]y = 2x  4[/tex]
Because the required equation and [tex]y = 2x  4[/tex] are parallel, then they must have the same slope
A linear equation is represented as:
[tex]y = mx + c[/tex]
Where:
[tex]m = slope[/tex]
So, by comparison
[tex]m = 2[/tex]
This means that the slope of the required line is 2
The equation is then calculated as:
[tex]y = m(x  x_1) + y_1[/tex]
So, we have:
[tex]y = 2(x2) + 1[/tex]
[tex]y = 2(x+2) + 1[/tex]
Open brackets
[tex]y = 2x+4 + 1[/tex]
[tex]y = 2x+5[/tex]
Hence, the equation of the line is: [tex]y = 2x+5[/tex]
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