Three different ways to put 6(3x + 8) + 32 + 12x
Mathematics
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Question
Three different ways to put 6(3x + 8) + 32 + 12x
1 Answer

1. User Answers SaniShahbaz
Answer:
Writing 6(3x + 8) + 32 + 12x in 3 different ways:
 w₁ = 18x + 48 + 32 + 12x
∵ 6(3x + 8) = 18x +48 as distribute law suggests that a(b + c) = ab + ac
 w₂ = 18x + 80 + 12x ∵ 48 + 32 = 80
 w₂ = 30x + 80 ∵ 18x + 12x = 30x
Stepbystep explanation:
As the expression is 6(3x + 8) + 32 + 12x, and we have to write it in three different ways. Using the properties of operations we can write it in three different ways,
Let way one be denoted as w₁
Let way two be denoted as w₂
Let way three be denoted as w₃
So, lets write 6(3x + 8) + 32 + 12x in 3 different ways:
 w₁ = 18x + 48 + 32 + 12x
∵ 6(3x + 8) = 18x +48 as distribute law suggests that a(b + c) = ab + ac
 w₂ = 18x + 80 + 12x ∵ 48 + 32 = 80
 w₂ = 30x + 80 ∵ 18x + 12x = 30x
Keywords: operation properties, distributive law
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