14 What would be the slope of equation #1 in the following system? (Graphing) 2x+3y=12 4x3y=15 (Worth 10 points ) A:1/2 B: 1 C:3/4 D:2/3
Mathematics
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Question
14
What would be the slope of equation #1 in the following system? (Graphing)
2x+3y=12
4x3y=15
(Worth 10 points )
A:1/2
B: 1
C:3/4
D:2/3
What would be the slope of equation #1 in the following system? (Graphing)
2x+3y=12
4x3y=15
(Worth 10 points )
A:1/2
B: 1
C:3/4
D:2/3
1 Answer

1. User Answers MrRoyal
Answer:
[tex]m = \frac{2}{3}[/tex]
Stepbystep explanation:
Given
[tex]2x+3y=12[/tex]
[tex]4x3y=15[/tex]
Required
Slope of #1
[tex]2x+3y=12[/tex]
Make y the subject
[tex]3y = 2x + 12[/tex]
Divide through by 3
[tex]y = \frac{2}{3}x + \frac{12}{3}[/tex]
[tex]y = \frac{2}{3}x + 4[/tex]
An equation has the form:
[tex]y = mx + c[/tex]
Where
[tex]m = slope[/tex]
Compare [tex]y = mx + c[/tex] and [tex]y = \frac{2}{3}x + 4[/tex]
[tex]m = \frac{2}{3}[/tex]
Hence, the slope is [tex]\frac{2}{3}[/tex]