Mathematics

Question

Write the equation of a line with that passes through the
points (-3, -2) and (6,1)?

1 Answer

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    : Y = 1/3x - 1

    :

    M = y2 - y1/ x2-x1

    M = 6 - (-3) / 1 - (-2)

    Y = 1/3x + b

    Then substitute one of the points into the equation

    -2= 1/3(-3) + b

    -2 + 2 + b = 1/3(-3) +b - b + 2

    -b = 1/3(-3) + 2

    -b = 1

    b = -1

    Y = 1/3x - 1

    Then i plugged it into

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