A copper alloy cylinder that is 1.3 feet long with a diameter of 45.27 inch is subjected to a tensile stress of 1,140 psi along its length. Assuming this applie
Engineering
jtbennett1348
Question
A copper alloy cylinder that is 1.3 feet long with a diameter of 45.27 inch is subjected to a tensile stress of 1,140 psi along its length. Assuming this applied stress is purely elastic, calculate the diameter, in inches, of the cylinder under this load. For this alloy, the elastic modulus is 904,672 psi and the Poisson's ratio is 0.33.
1 Answer

1. User Answers ogorwyne
Answer:
diameter = 45.251 inches
Explanation:
initial length = 1.3
initial diameter = 45.27
tensile stress = σ = 1140
modulus E = 904672
v = 0.33
we calculate longitudinal strain = σ/E
= 1140/904672
= 0.0012601252
general relation for
v = Ed/El
[tex]0.33=\frac{Ed}{0.0012601252}[/tex]
we cross multiply
Ed = 0.33 x 0.0012601252
= 0.00041584132in
[tex]\frac{df  45.27}{45.27} =\frac{0.00041584132}{1}[/tex]
when we cross multiply,
df  45.27 = 0.00041584132*45.27
df  45.27 = 0.018825136
df = 0.018825136 + 45.27
df = 45.251 inches