solve the system of equations below y=3/2x2 and 2x+y=4
Mathematics
timothy566
Question
solve the system of equations below y=3/2x2 and 2x+y=4
2 Answer

1. User Answers campbellst2005
rewrite the 2nd equation as
y = 4 2x
then substitute into the 1st equation so you get
[tex]4  2x = \frac{3}{2} x  2[/tex]
then solve for x.
when you get the value of x, substitute it into either equation to find y
hope it helps 
2. User Answers apologiabiology
since y=(3/2)x2
subsitute 3/2x2 for y in 2nd equation
2x+3/2x2=4
add 2 to both sides
2x+3/2x=2
times 2 both sides
4x+3x=4
7x=4
divide both sides by 7
x=4/7
sub that back
y=3/2x2
y=3/2(4/7)2
y=12/142
y=6/72
y=6/714/7
y=20/7
(x,y)
(4/7,20/7)