Mathematics

Question

solve the system of equations below y=3/2x-2 and 2x+y=-4

2 Answer

  • rewrite the 2nd equation as 

    y = -4 -2x

    then substitute into the 1st equation so you get

    [tex]-4 - 2x = \frac{3}{2} x - 2[/tex]

    then solve for x. 

    when you get the value of x, substitute it into either equation to find y

    hope it helps
  • since y=(3/2)x-2
    subsitute 3/2x-2 for y in 2nd equation
    2x+3/2x-2=-4
    add 2 to both sides
    2x+3/2x=-2
    times  2 both sides
    4x+3x=-4
    7x=-4
    divide both sides by 7
    x=-4/7
    sub that back
    y=3/2x-2
    y=3/2(-4/7)-2
    y=-12/14-2
    y=-6/7-2
    y=-6/7-14/7
    y=-20/7


    (x,y)
    (-4/7,-20/7)
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