Given a mean of 43.8 and a standard deviation of 8.7, what is the zscore of the value 40 rounded to the nearest tenth?
Mathematics
kValeycrapo
Question
Given a mean of 43.8 and a standard deviation of 8.7, what is the zscore of the value 40 rounded to the nearest tenth?
2 Answer

1. User Answers MissPhiladelphia
For the answer to the question above,
Sample mean is given by,
x = (1/n)∑x˅i .... ˅ means sub
x = (1/5)(60 + 40 + 35 + 45 + 39)
= 43.8
zscore is given by,
z = (X  μ)/σ .... μ is population mean, σ is the standard deviation
z = (43.8  43.8)/8.7
= 0
so the answer is zero
I hope my answer helped you. 
2. User Answers heyyitsnyy
Answer:
.4
Stepbystep explanation:
z score = valuemean / standard deviation
z score = 4043.8 / 8.7
.436 = 4043.8 / 8.7
.436 to nearest 10th .4