The area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room. which equations can be used to solve for y,
Question
2 Answer

1. User Answers Anonym
I hope this helps you 
2. User Answers dsavellanedaj
Answer:
Width=25 ft and length=30 ft
Stepbystep explanation:
In order to find the answer let's remember that the area (A) of a rectangle is:
[tex]A=width*length[/tex]
Let's assume that the length of the room is 'X' feet.
Becuase the problem mentioned that the width (Y) of the room is 5 feet less than the length, then:
[tex]Y=X5[/tex]
Now, using the area equation we have:
A=width*length
[tex]750=X*Y[/tex] but using the width expression we have:
[tex]750=X*(X5)[/tex]
[tex]0=X^25X750[/tex]
Using the root's equation we have:
[tex]X=\frac{b\±\sqrt{b^{2}4ac}}{2a}[/tex]
[tex]X=\frac{(5)\±\sqrt{(5)^{2}(4*1*(750)}}{2*1}[/tex]
[tex]X1=30[/tex]
[tex]X1=25[/tex]
Because the length (X) can't be negative, then length=30 feet. In order to find the width we have:
[tex]Y=X5[/tex]
[tex]Y=305[/tex]
[tex]Y=25[/tex]
So the width is 25 feet.
In conclusion the room has a width=25 ft and length=30 ft.