A 50.Newton horizontal force is needed to keep an object weighing 500. Newtons moving at a constant velocity of 2.0 meters per second across a horizontal surfa
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Question
A 50.Newton horizontal force is needed to keep an object weighing 500. Newtons moving at a constant velocity of 2.0 meters per second across a horizontal surface. The magnitude of the frictional force acting on the object is
2 Answer

1. User Answers AL2006
 "Constant velocity" means the acceleration of the object is zero.
 "Zero acceleration" means that all the forces on the object add up to zero.
 If a force of 50newtons is pulling the object in one direction
and the object's speed is constant, then the frictional force on
the object must be 50 newtons in the opposite direction. 
2. User Answers ahirohit963
The magnitude of the frictional force acting on the object is 50 N.
Given :
Horizontal Force = 50 N
Object weight = 500 N
Constant Velocity = 2 m/sec
Solution 
Constant velocity means acceleration is zero. And from Newton's second law of motion,
[tex]\rm \sum F = ma[/tex]  (1)
Here a = 0, therefore from equation (1) we get:
[tex]\rm \sum F = 0[/tex]
[tex]\rm F_1  50 = 0[/tex]
where [tex]\rm F_1[/tex] is friction force,
[tex]\rm F_1 = 50 \;N[/tex]
The magnitude of the frictional force acting on the object is 50 N.
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