Mathematics

Question

Solve using quadratic formula. 2x^2+6x+3=0

1 Answer

  • [tex]x = \frac{-b +/- \sqrt{b^{2} -4ac} }{2a} [/tex]

    a = 2
    b = 6
    c = 3

    [tex]x = \frac{-6 +/- \sqrt{6^{2} -4*2*3} }{2*2} [/tex]

    [tex]x = 0.634[/tex] orĀ [tex]x = -2.366[/tex]
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