Help please!! I will mark brainilist and give a lot of points. This is Pythagorean theorem. Formula: a^2+b^2=c^2 When I say ^2 I mean to the power of 2. The qu
Mathematics
lena3056
Question
Help please!! I will mark brainilist and give a lot of points.
This is Pythagorean theorem.
Formula: a^2+b^2=c^2
When I say ^2 I mean to the power of 2.
The question is asking me to solve for a.
Then give me b and c which is b = 17 1/3 and c = 16.
How do I solve for a when b is greater than c? Won’t that give me a negative a? You can’t have a negative a right?
Unless I’m wrong.
Please help my solve this!!!!! :D
This is Pythagorean theorem.
Formula: a^2+b^2=c^2
When I say ^2 I mean to the power of 2.
The question is asking me to solve for a.
Then give me b and c which is b = 17 1/3 and c = 16.
How do I solve for a when b is greater than c? Won’t that give me a negative a? You can’t have a negative a right?
Unless I’m wrong.
Please help my solve this!!!!! :D
1 Answer

1. User Answers Anonym
Hello there,
 I just looked into the question and you are absolutely right whatever you inferred.
 I think the question might be wrong.
 The value of c should be greater than b.
 I guess it will like this:
 [tex]b = 16 \: \: \: c = 17 \frac{1}{3} [/tex]
 The values should be like this.
 I am solving the equation by this:
 [tex] {a}^{2} = {c}^{2}  {b}^{2} \\ = > {a}^{2} = {(17 \frac{1}{3}) }^{2}  {(16)}^{2} \\ = > {a}^{2} = {( \frac{52}{3} )}^{2}  {(16)}^{2} \\ = > {a}^{2} = ( \frac{52}{3}  16)( \frac{52}{3} + 16) \\ = > {a}^{2} = ( \frac{52  48}{3} )( \frac{52 + 48}{3} ) \\ = > {a}^{2} = \frac{4}{3} \times \frac{100}{3} \\ = > {a}^{2} = \frac{400}{9} \\ = > a = \sqrt{ \frac{400}{9} } \\ = > a = \frac{20}{3} \\ = > a = 6 \frac{2}{3} [/tex]
 So, the value of a is
[tex]a = 6 \frac{2}{3} [/tex]
Hope you could get an idea from it.
Doubt clarification  use comment section.