I'm completely lost on this question please help
Mathematics
mynameisem
Question
I'm completely lost on this question please help
2 Answer

1. User Answers apologiabiology
first, note that y≠0 and y≠4 because that would make the denomenators 0 which is undefined
we got to get rid of fractions
common denomenator is y(y4)
multiply both sides by y(y4)
2y+y4=y(y1)
3y4=y²y
minus 3y both sides
4=y²4y
add 4 both sides
0=y²4y+4
factor
what 2 numbers multiply to get 4 and add to get 4?
2 and 2
0=(y2)(y2)
set to zero
y2=0
y=2
no extranious roots
y=2 is the solution 
2. User Answers wolf1728
Multiply the numerators by "y" which yields:
(2y) / (y4) +1 = (y^2 y) / (y4)
(2y) / (y4)  (y^2 y) / (y4) = 1
(2y)  (y^2 y) / (y4) = 1
(2y)  (y^2 y) = y +1
y^2 +2y y +y = 1
y^2 +2y 1 = 0
Multiplying by 1
y^2 2y +1 = 0
(y 1) * (y  1) = 0
x = 1
x= 1