Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms. The bottle slides down the hill and is movi
Physics
aundria12
Question
Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms. The bottle slides down the hill and is moving at a velocity of 14 meters/second the instant it hits the ground. The vertical height from where Jeff dropped the bottle is meters. Ignore friction, and use , PE = m × g × h, and g = 9.8 m/s2.
2 Answer

1. User Answers aristocles
Answer:
h = 10 m
Explanation:
As per energy conservation law we know that if there is no friction force present in the system then in that case total energy is always remains conserved.
So here we can say that
initial potential energy = final kinetic energy
[tex]\frac{1}{2}mv^2 = mgh[/tex]
here we know that
m = 0.25 kg
v = 14 m/s
now from above equation
[tex]\frac{1}{2}(0.25)(14)^2 = 0.25(9.8)(h)[/tex]
[tex]h = 10 m[/tex]
so initial vertical height will be h = 10 m

2. User Answers clouse617140
Answer:
h=10m
1/2(0.25)(14)^2=0.25(9.8)(h)