Dani has 15.00 grams of water (c = 4.186 ) at 66°C. She adds 40.00 grams of water at 35°C. What is the final temperature of the liquids? Express the answer to t
Physics
frankharley
Question
Dani has 15.00 grams of water (c = 4.186 ) at 66°C. She adds 40.00 grams of water at 35°C. What is the final temperature of the liquids? Express the answer to the hundredths place.
2 Answer

1. User Answers maddieayala
Answer:
43.45°C
Explanation:
Subtract 273 from 316.45 K to get the answer in Celsius.

2. User Answers facundo3141592
Answer: 43.45°C
Explanation:
The equation for the final temperature is:
T = (T1*m1 + T2*m2)/(m1 + m2)
Where:
T1 = 66 + 273.15 = 339.15 k
T2 = 35 + 273.15 = 308.15 k
(you need to convert the temperatures into kelvin degrees)
m1 = 15g
m2 = 40g
T = (15g*339.15k + 40g*308.15k)/(15g + 40g) = 316.6k
Returning to the celcius notation:
T = 316.6  273.15 = 43.45°C