What is partial derivative of z=(2x+3y)^10 with respect to x,y?

2 Answer

  • Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.

    [tex]\dfrac\partial{\partial x}(2x+3y)^{10}=10(2x+3y)^9\times2=20(2x+3y)^9[/tex]

    [tex]\dfrac\partial{\partial y}(2x+3y)^{10}=10(2x+3y)^9\times3=30(2x+3y)^9[/tex]

    Or, if you actually did want the second order derivative,

    [tex]\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8[/tex]

    and in case you meant the other way around, no need to compute that, as [tex]z_{xy}=z_{yx}[/tex] by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because [tex]z[/tex] is a polynomial).
  • Answer:

    Step-by-step explanation:

    Given that z is a function of x,y


    Partially differentiate wrt x and y separately to get

    [tex]\dfrac\partial{\partial x}(2x+3y)^{10}=10(2x+3y)^9\times2=20(2x+3y)^9\\\dfrac\partial{\partial y}(2x+3y)^{10}=10(2x+3y)^9\times3=30(2x+3y)^9[/tex]