Chemistry

Question

Consider the reaction below. H2(g) + CO2(g) mc013-1.jpg H2O(g) + CO(g) At equilibrium at 600 K, the following are true. [CO2] = 9.5 x 10-4 M [H2] = 4.5 x 10-2 M [H2O] = 4.6 x 10-3 M [CO] = 4.6 x 10-3 M What is the value of the equilibrium constant for this reaction in correct scientific notation? 4.9 x 10-3 4.9 x 10-2 4.9 x 10-1 4.9 x 103

2 Answer

  • The correct answer is C
  • Ans: c) 4.9 *10-1

    Given:

    Concentrations of the reactants and products-

    [CO2] = 9.5 x 10-4 M

    [H2] = 4.5 x 10-2 M

    [H2O] = 4.6 x 10-3 M

    [CO] = 4.6 x 10-3 M

    To determine:

    The equilibrium constant K

    Explanation:

    The given reaction is:

    H2(g) + CO2(g) ↔ H2O(g) + CO(g)

    The equilibrium constant is given as:

    [tex]K = \frac{[H2O]*[CO]}{[H2]*[CO2]} \\\\K = \frac{4.6 x 10^{-3}  M * 4.6 x 10^{-3}  M}{4.5 x 10^{-2} 10-2 M*9.5 x 10^{-4}  M} \\\\K = 0.4949 = 4.9 *10^{-1}  [/tex]

NEWS TODAY