Mathematics

Question

Sandra is selling red and yellow roses. On the first day she sold 4 red roses and 1 yellow rose for a total of $7. On the second day she sold 3 red roses and 1 yellow rose for a total of $6. What was the price of the two types of roses?



PLEASE EXPLAIN!!!!:)

2 Answer

  • R is red and Y is yellow

    4R+Y=7

    3R+Y=6

    ----------subtract

    R=1

    4R+Y=7

    4(1)+Y=7

    Y=7-4

    Y=3

    answer: Yellow is $3, Red is $1


  • Let, the price of red rose = x
    Price of yellow rose = y

    Now, Equations would be: 4x + y = 7
    3x + y = 6

    Subtract 2nd equation from 1st, 
    x = 1

    Now, substitute it in 2nd equation, 
    3(1) + y = 6
    y = 6 - 3 = 3

    In short, Price of red rose = $1 & Price of a yellow rose = $3

    Hope this helps!
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