Sandra is selling red and yellow roses. On the first day she sold 4 red roses and 1 yellow rose for a total of $7. On the second day she sold 3 red roses and 1
Mathematics
squishycomeon
Question
Sandra is selling red and yellow roses. On the first day she sold 4 red roses and 1 yellow rose for a total of $7. On the second day she sold 3 red roses and 1 yellow rose for a total of $6. What was the price of the two types of roses?
PLEASE EXPLAIN!!!!:)
PLEASE EXPLAIN!!!!:)
2 Answer

1. User Answers Anonym
R is red and Y is yellow
4R+Y=7
3R+Y=6
subtract
R=1
4R+Y=7
4(1)+Y=7
Y=74
Y=3
answer: Yellow is $3, Red is $1

2. User Answers Anonym
Let, the price of red rose = x
Price of yellow rose = y
Now, Equations would be: 4x + y = 7
3x + y = 6
Subtract 2nd equation from 1st,
x = 1
Now, substitute it in 2nd equation,
3(1) + y = 6
y = 6  3 = 3
In short, Price of red rose = $1 & Price of a yellow rose = $3
Hope this helps!