Find the resultant displacement of a bear searching for berries on the mountain. The bear heads 55.0º north of west for 15.0 m; then it turns and heads to the w
Question
2 Answer

1. User Answers Anonym
North component: y = 15.0 m * sin 55.0º = 12.3 m
West component: x = 15.0 m * cos 55.0º + 7.00 m = 15.6 m
so his heading, measured from West, is
Θ = arctan(y/x) = arctan0.787 = 38.2º N of West
and measured from North is
φ = arctan(x/y) = arctan(1.27) = 51.8º W of North
Hope this helps! 
2. User Answers Muscardinus
Answer:
Resultant, d = 19.9 meters
Explanation:
It is given that,
The bear heads 55 degrees north of west for 15.0 m; then it turns and heads to the west for another 7.00 m. The attached figure shows the whole scenario.
The net displacement of bear due north is given by :
[tex]d_n=15\ sin\theta[/tex]
[tex]d_n=15\ sin(55) = 12.28\ m[/tex]
The net displacement of bear due west is given by :
[tex]d_w=15\ cos\theta+7[/tex]
[tex]d_w=15\ cos(55)+7=15.60\ m[/tex]
Let d is the resultant displacement of a bear searching for berries on the mountain. It can be calculated as :
[tex]d=\sqrt{d_n^2+d_w^2}[/tex]
[tex]d=\sqrt{12.28^2+15.60^2}[/tex]
d = 19.85 meters
or
d = 19.9 meters
So, the resultant displacement of a bear is 19.9 meters. Hence, this is the required solution.