Mathematics

Question

What is the equation of a circle with center (6,4) that passes through the coordinate (2,1)?

2 Answer

  • The answer is going to be (2,2) 
  • first find the radius of circle by finding the length from center to the given point

    well we  need the square of radius  r^2 = (6-2)^2 + (4-1)^2 = 25

    equation of circle is (x - a)^2 + (y - b)^2 = r^2  where (a,b) is the center
    so our circle is  
           (x - 6)^2 + ( y - 4)^2 = 25
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