Mathematics

Question

Can someone help with problem 1 and/or 3?
Can someone help with problem 1 and/or 3?

1 Answer

  • #1

    88+100+72+94=354 ---first 4 tests total

    if he needs an average of 90, the total of 5 tests must = 90x5=450

    450 - 354 = 96

    answer: his last test he needs to make 96 in order to average 90

    #3

    n, n+2, n+4 are 3 consecutive even numbers

    4(n+n+2) = 2(n+4)

    4(2n+2)=2(n+4)

    8n+8 = 2n + 8

    6n = 0

    n = 0

    n+2=0+2=2

    n+4=0+4=4

    answer: 3 consecutive even numbers are 0,2,4

    double check

    4 times sum of first and second equals twice the third

    4(n+n+2) = 2(n+4)

    4(0+0+2)=2(0+4)

    4(2)=2(4)

    8=8



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