Mathematics

Question

y=x^2+12x+10 -8x+y=10

1 Answer

  • sub x^2+12x+10 for y in other equaiton

    -8x+x^2+12x+10=10
    x^2+4x+10=10
    minus 10 both sides
    x^2+4x=0
    factor
    (x+4)(x)=0
    set to zer

    x+4=0
    x=-4

    x=0

    x=-4 or 0
    sub back

    y=0^2+12(0)+10, y=10
    (0,10)

    y=(-4)^2+12(-4)+10, y=-22
    (-4,-22)



    solutions are
    (0,10) and (-4,-22)
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