normal distributed mean of 200pounds and a standard deviation of 20 pounds what percent would be over 250 pounds
Mathematics
rossd63
Question
normal distributed mean of 200pounds and a standard deviation of 20 pounds what percent would be over 250 pounds
1 Answer

1. User Answers LammettHash
[tex]\mathbb P(X>250)=\mathbb P\left(\dfrac{X200}{20}>\dfrac{250200}{20}\right)=\mathbb P(Z>2.5)\approx0.0062=0.62\%[/tex]