1)question the rate of piece of gift paper is Rs. 0.40 per paper. how many pieces of paper can we purchase for Rs. 78.40 2)question A shopkeeper sold a toy for
Question
the rate of piece of gift paper is Rs. 0.40 per paper. how many pieces of paper can we purchase for Rs. 78.40
2)question
A shopkeeper sold a toy for Rs. 96 at a loss of 20% find the loss
3)question
if a car needs 9 litres of petrol for a journey of 162km. Find how many litres of petrol is required for 306km?
4)question
solve the equation 3x1.5 by 0.91.5=0 and verify the solution
5)question
A room is triangular in shape. Its base is 9.4m and height is 8.6m.Find at the rate in rs. 250 per square metre.
6)question
subtract
[tex] {3}x ^{5}  {4}x^{4} + {8}x^{3}  6 from {8}x^{5} + {5}x^{4}  {3}x^{3} + 4x + 3.[/tex]
1 Answer

1. User Answers TheUnknownScientist
Answer:
Question 1
Given
 The rate of piece of gift paper is Rs. 0.40 per paper.
So,
78.40 ÷ 0.40 = 196
Thus, We can purchase 196 pieces of paper.
Question 2
Given
 A shopkeeper sold a toy for Rs. 96 at a loss of 20%.
Here,
Loss of 20% means Rs 96 represents 80% of cost price.
Therefore,
CP = 96/80 × 100 = 120
So,
₹120  ₹96 = ₹24
Thus, The loss is ₹24
Question 3
Given
 A car needs 9 litres of petrol for a journey of 162km.
Here, We will find that how much km the car drive in 1 litre of petrol,
So,
162 ÷ 9 = 18 km
Now, we need to find for 306 km.
306 ÷ 18 = 17
Thus, 17 litres of petrol required for 306 km.
Question 4
(3x  1.5) ÷ (0.9  1.5) = 0
(3x  1.5) ÷ (0.6) = 0
3x  1.5 = 0
3x = 1.5
x = 1.5/3 = 0.5
VERIFICATION
(3x  1.5) ÷ (0.9  1.5) = 0
[3(0.5)  1.5] ÷ (0.9  1.5) = 0
(1.5  1.5) ÷ (0.6) = 0
0 ÷ (0.6) = 0
0 = 0
Hence Verified!!
Question 5
Given
 A room is triangular in shape.
 Base (b) = 9.4m
 Height (h) = 8.6m
Formula
 Area = ½ × Base × Height
So,
A = 1/2 × 9.4 × 8.6 = 40.42 m²
We are given that the rate of per square metre is ₹250.
So,
40.42 × 250 = ₹10,105
Thus, the rate of 40.42 m² is ₹10,105.
Question 6
(8x⁵ + 5x⁴  3x³ + 4x + 3)
(3x⁵  4x⁴ + 8x³  0x  6)
 +  + +
5x⁵ + 9x⁴  11x³ + 4x + 9
Thus, The answer is (5x⁵ + 9x⁴  11x³ + 4x + 9).