Mathematics

Question

Robyn adopted a child who is exactly 28 years younger than her.
In one year's time, Robyn will be 3 times as old as her child will be.
How old is Robyn now?

2 Answer

  • Answer:

    Robyn is 41years

    Step-by-step explanation:

    let's represent Robyn age as x

    so Robyn=x

    child=x-28

    In a year time

    Robyn=x+1

    child=x-28+1 =x-27

    "Robyn will be three times as old as her child"

    here multiply 3 by the child's age

    child=3(x-27)

    =3x-81

    hence,x-1=3x-81. (group like terms)

    x-3x=(-81-1)

    -2x=-82 (divide both side by -2)

    x=-82/-2

    x=41

    Therefore Robyn's age is 41

  • Answer:

      Robyn is 41

    Step-by-step explanation:

    You want to know Robyn's current age if she will be 3 times as old as her 28-year younger daughter in one year from now.

    Ratio units

    The difference in ages remains constant. When Robyn is 3 times as old as her daughter, the ratio of their ages is ...

      Robyn : daughter = 3 : 1

    The difference in their ages is 3 -1 = 2 ratio units. Each ratio unit stands for 28/2 = 14 years, so Robyn's age of 3 ratio units represents 42 years.

    That will be 1 year from now, so Robyn is 41.

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