Robyn adopted a child who is exactly 28 years younger than her. In one year's time, Robyn will be 3 times as old as her child will be. How old is Robyn now?
Question
In one year's time, Robyn will be 3 times as old as her child will be.
How old is Robyn now?
2 Answer

1. User Answers zuwairayakubu2007
Answer:
Robyn is 41years
Stepbystep explanation:
let's represent Robyn age as x
so Robyn=x
child=x28
In a year time
Robyn=x+1
child=x28+1 =x27
"Robyn will be three times as old as her child"
here multiply 3 by the child's age
child=3(x27)
=3x81
hence,x1=3x81. (group like terms)
x3x=(811)
2x=82 (divide both side by 2)
x=82/2
x=41
Therefore Robyn's age is 41

2. User Answers sqdancefan
Answer:
Robyn is 41
Stepbystep explanation:
You want to know Robyn's current age if she will be 3 times as old as her 28year younger daughter in one year from now.
Ratio units
The difference in ages remains constant. When Robyn is 3 times as old as her daughter, the ratio of their ages is ...
Robyn : daughter = 3 : 1
The difference in their ages is 3 1 = 2 ratio units. Each ratio unit stands for 28/2 = 14 years, so Robyn's age of 3 ratio units represents 42 years.
That will be 1 year from now, so Robyn is 41.