Find 4 consecutive odd integers , such that 5 times the second is equal to one more than eight times the smalller
Mathematics
azeemzaman23
Question
Find 4 consecutive odd integers , such that 5 times the second is equal to one more than eight times the smalller
2 Answer

1. User Answers zarampa
Answer:
The numbers are:
3, 5, 7 and 9
Stepbystep explanation:
a = first odd number or "the smaller"
a+2 = second consecutive odd number
a+4 = third consecutive odd number
a+6 = fourth consecutive odd number
Then:
5(a+2) = 1 + 8(a)
(5*a + 5*2) = 1 + 8a
5a + 10 = 1 + 8a
10  1 = 8a  5a
9 = 3a
9/3 = a
a = 3
a+2 = 5
a+4 = 7
a+6 = 9
Check:
5(5) = 1 + 8(3)
25 = 1 + 24

2. User Answers mhanifa
Answer:
 The integers are 3, 5, 7 an d 9

The difference between consecutive integers is 2.
Let the smallest be n, then we have the following equation:
 5(n + 2) = 8n +1
Solve it for n:
 5n + 10 = 8n + 1
 8n  5n = 10  1
 3n = 9
 n = 3
The other integers are 5, 7, 9.