Y=3/2x+9 2x+2y=16 how to solve it by using substitution
Mathematics
Ragin2016
Question
Y=3/2x+9 2x+2y=16 how to solve it by using substitution
2 Answer

1. User Answers Anonym
y=3/2x+9
or
y+3/2x=9, or 2y+3x=18
2y+2x=16. 
2y+2x=16
x=2
y=6. Hope it help! 
2. User Answers cher
Equation 1) y = 3/2x + 9
Equation 2) 2x + 2y = 16
Add 3/2x to both sides of equation 1.
1) 3/2x + y = 9
Then, multiply all of equation one by 2.
1) 2(3/2x + y = 9)
1) 3x + 2y = 18
2) 2x + 2y = 16
Subtract.
x = 2
Plug in 2 for x in the first equation.
y=3/2x+9
y = 3/2(2) + 9
y = 3 + 9
y = 6
So, x=2 and y = 6
~Hope I helped!~