What is the percent by mass of oxygen in Fe2O3 (formula mass = 160)?
Question
2 Answer

1. User Answers Mergus
Answer:
30 %
Explanation:
From the formula of [tex]Fe_2O_3[/tex], it is evident that:
1 mole of [tex]Fe_2O_3[/tex] contains 3 moles of O atom
Also, molar mass of O = 16 g/mol
So, mass of 3 moles = 16*3 g = 48 g
Percent composition or percent by mass is percentage by the mass of element present in the compound.
Mass of 1 mole of the compound = 160 g
[tex]\%\ Composition\ of\ oxygen=\frac{Mass_{oxygen}}{Total\ mass}\times 100[/tex]
[tex]\%\ Composition\ of\ oxygen=\frac{48}{160}\times 100[/tex]
[tex]\%\ Composition\ of\ oxygen=30\ \%[/tex]

2. User Answers Abdulazeez10
The percent by mass of oxygen in Fe₂O₃ is 30%
Percentage by mass
From the question,
We are to determine the percent by mass of oxygen in Fe₂O₃
The percent by mass of oxygen in the compound can be calculated by using the formula,
[tex]Percent\ by \ mass\ of \ oxygen = \frac{Mass \ of \ oxygen \ in \ the \ compound}{Mass \ of \ the \ compound} \times 100\%[/tex]
Mass of oxygen in the compound = 3 × 16 = 48 g
Therefore,
[tex]Percent\ by \ mass\ of \ oxygen = \frac{48}{160} \times 100\%[/tex]
[tex]Percent\ by \ mass\ of \ oxygen = 30\%[/tex]
Hence, the percent by mass of oxygen in Fe₂O₃ is 30%
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