Chemistry

Question

What is the percent by mass of oxygen in Fe2O3 (formula mass = 160)?

2 Answer

  • Answer:

    30 %

    Explanation:

    From the formula of [tex]Fe_2O_3[/tex], it is evident that:-

    1 mole of [tex]Fe_2O_3[/tex] contains 3 moles of O atom

    Also, molar mass of O = 16 g/mol

    So, mass of 3 moles = 16*3 g = 48 g

    Percent composition or percent by mass is percentage by the mass of element present in the compound.

    Mass of 1 mole of the compound = 160 g

    [tex]\%\ Composition\ of\ oxygen=\frac{Mass_{oxygen}}{Total\ mass}\times 100[/tex]

    [tex]\%\ Composition\ of\ oxygen=\frac{48}{160}\times 100[/tex]

    [tex]\%\ Composition\ of\ oxygen=30\ \%[/tex]

  • The percent by mass of oxygen in Fe₂O₃ is 30%

    Percentage by mass

    From the question,

    We are to determine the percent by mass of oxygen in Fe₂O₃

    The percent by mass of oxygen in the compound can be calculated by using the formula,

    [tex]Percent\ by \ mass\ of \ oxygen = \frac{Mass \ of \ oxygen \ in \ the \ compound}{Mass \ of \ the \ compound} \times 100\%[/tex]

    Mass of oxygen in the compound = 3 × 16 = 48 g

    Therefore,

    [tex]Percent\ by \ mass\ of \ oxygen = \frac{48}{160} \times 100\%[/tex]

    [tex]Percent\ by \ mass\ of \ oxygen = 30\%[/tex]

    Hence, the percent by mass of oxygen in Fe₂O₃ is 30%

    Learn more on Percentage by mass here: https://brainly.com/question/14308710

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