A student factored 6 x^9y^2 +2xy as 2xy(3x^8y) What went wrong? Factor correctly.
Mathematics
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Question
A student factored 6 x^9y^2 +2xy as 2xy(3x^8y) What went wrong? Factor correctly.
1 Answer

1. User Answers kemanci
In the problem that the student factored incorrectly, they left out a term. Even though you factored out 2xy, you still need to leave a 1 in its place, so you can distribute it back out. If you distribute out the incorrectly factored equation, you will get 6x^9y^2. If you distribute out 2xy(3x^8y+1), you will get 6x^9y^2+2xy.