Consider circle T with radius 24 in. and θ = 5pi/6 radians. What is the length of minor arc SV? 20π in. 28π in. 40π in. 63π in.
Question
20π in.
28π in.
40π in.
63π in.
2 Answer

1. User Answers carlosego
By definition, the arc length is given by:
[tex] S = R * theta
[/tex]Where,
R: radius of the circle
theta: central angle
Therefore, substituting values we have:
[tex] S = (24) * (\frac{5}{6}\pi)
S = 20\pi
[/tex]Thus, the length of the minor arc SV is given by:
20π in
Answer:
the length of minor arc SV is:
20π in
option 1

2. User Answers lhabdulsamirahmed
The length of the arc is equal to 20π in
Data;
 θ = 5π/6 radians
 radius = 24in
Length of an Arc
To find the length of the arc, we can either convert the angle from radians to degree and solve.
[tex]1rad * 180/\pi = degree\\5\pi /6 * 180/\pi = ?\\5/6 * 180 = 150^0[/tex]
The length of an arc is given as
[tex]L_a_r_c= \frac{\theta}{360}*2\pi r\\ L_a_r_c = \frac{150}{360} *2\pi *24\\ L_a_r_c = 20\pi[/tex]
From the calculation above, the length of the arc is equal to 20π.
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