Mathematics

Question

how many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20

2 Answer

  • Answer: 0

    Step-by-step explanation:

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  • There will be four solutions to the system of equations.

    What is a quadratic equation?

    An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, and a must not be zero.

    For example 3x² + 6x + 8 = 0 here x has highest term as 3 and coefficient of x² is not zero

    Given equation are

    x² + 4y² = 100 and

    4y - x² = -20 ⇒ x² = 4y + 20

    By substituting into the first equation

    4y² + 4y = 80

    Since in quadratic equation there will be 2 solutions,

    Corresponding to y's solution there will be 2 x's solution.

    So there will be total of 4 x's solutions.

    So the number of solution for the given equation will be 4.

    For more about the quadratic equation,

    https://brainly.com/question/17177510

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