Write an equation for the line that is parallel to the given line and that passes through the given point. y = –5x + 3; (–6, 3) A) y = –5x – 27 B) y = –5x + 27
Mathematics
bosticsm17
Question
Write an equation for the line that is parallel to the given line and that passes through the given point. y = –5x + 3; (–6, 3)
A) y = –5x – 27
B) y = –5x + 27
C) y = 5x – 9
D) y = –5x + 9
A) y = –5x – 27
B) y = –5x + 27
C) y = 5x – 9
D) y = –5x + 9
2 Answer

1. User Answers hrharter1hrharter1
You would need a new yintercept in order for this to be parallel. So you use the points given and the slope and fill it in. 3=5(6)+b. 3=30+b. Then subtract 30 from both sides. 27=b. Then just put it all back into slope intercept form. y=5x27. 
2. User Answers skopie
Answer:
Stepbystep explanation:
y = –5x + 3
slope of the given line by comparing with y=mx+b is
m=  5
Concept is that the slope of parallel lines are equal so we need a line with slope same as m=5
and passes through point (6,3)
Equation using the point slope equation
y3 = 5 (x(6))
y3=5(x+6)
y3= 5x30
y= 5x 27
A