Suppose a binomial event has a probability of success of 0.3, and 1250 trials are performed. What is the standard deviation of the possible outcomes? Round your
Mathematics
kiwicaballero
Question
Suppose a binomial event has a probability of success of 0.3, and 1250 trials are performed. What is the standard deviation of the possible outcomes? Round your answer to two decimal places.
2 Answer

1. User Answers LammettHash
[tex]\sqrt{1250\times0.3\times(10.3)}\approx16.20[/tex] 
2. User Answers JeanaShupp
Answer: 16.20
Stepbystep explanation:
For any binomial event , the formula to calculate the standard deviation of the possible outcomes is given by :
[tex]\sigma=\sqrt{\text{p(1p)n}}[/tex]
Given: The probability of success p = 0.3
Then , the probability of failure q= 10.3=0.7
Now, by using above formula , the standard deviation of the possible outcomes will be :
[tex]\sigma=\sqrt{0.3\times0.7\times1250}\\\\\Rightarrow\sigma=\sqrt{262.5}\\\\\Rightarrrow\sigma=16.201851746\approx16.20[/tex]
Hence, the standard deviation of the possible outcomes = 16.20