n the waiting room of a vet's office, there are 4 cats, 5 dogs, 1 lizard, and 1 hamster. A represents the event that a randomly selected animal in this waiting
Mathematics
ElasticRavenHeart
Question
n the waiting room of a vet's office, there are 4 cats, 5 dogs, 1 lizard, and 1 hamster. A represents the event that a randomly selected animal in this waiting room is a dog. What is the probability of the complement of event A? Enter your answer as a fraction, in simplified form, in the box
2 Answer

1. User Answers Anonym
the answer 5/11. you add all those numbers up (thats the denominator) and put the 5 representing a dog on top of the fraction 
2. User Answers virtuematane
Answer:
The probability is:
[tex]\dfrac{6}{11}[/tex]
Stepbystep explanation:
There are 4 cats, 5 dogs, 1 lizard, and 1 hamster.
A represents the event that a randomly selected animal in this waiting room is a dog.
This means that the probability of A is the ratio of number of dogs to the total number of animals.
i.e.
[tex]P(A)=\dfrac{5}{11}[/tex]
( Since the total number of animals are: 11
and the total number of dogs=5 )
Also, the probability of complement of A is given by:
[tex]P(A^c)=1P(A)[/tex]
Hence,
[tex]P(A^c)=1\dfrac{5}{11}\\\\\\P(A^c)=\dfrac{115}{11}\\\\\\P(A^c)=\dfrac{6}{11}[/tex]
Hence, the answer is:
[tex]P(A^c)=\dfrac{6}{11}[/tex]