According to the fundamental theorem of algebra, how many zeros does the function f(x) = 17x15 + 41x12 + 13x3 − 10 have?
Mathematics
Bailey2230
Question
According to the fundamental theorem of algebra, how many zeros does the function f(x) = 17x15 + 41x12 + 13x3 − 10 have?
2 Answer

1. User Answers wolf1728
It should have 15 solutions.
The number of solutions depends on the term with with the highest exponent. 
2. User Answers flightbath
Answer: The given expression should have 15 zeroes
Explanation:
Fundamental theorem of algebra says the polynomial that have complex coefficient and highest power that is degree must have one complex root this involves real number because every real number is an imaginary number where imaginary part is equal to zero
General representation of complex number a+ib ; a and b are real numbers.
Number of zeroes depends on the degree of polynomial
Number of zeroes is equal to the highest power which is degree
Here degree is 15 hence, number of zeroes will be 15.