What is the number that follows in this sequence y1, 2y, 2, 4y4, 8y8, __ ??
Mathematics
michgarola
Question
What is the number that follows in this sequence y1, 2y, 2, 4y4, 8y8, __ ??
2 Answer

1. User Answers ag10712
16, because the pattern is to double the number each time. If you liked my answer please mark it the brainiest 
2. User Answers Equanimity
Given the sequence, the rule appears to be 2n.
(Y1)2 must be distributed. The result is 2Y  2. 2(2Y2) = 4Y4.
2(4Y  4) = 8Y  8.
The same rule will apply throughout the sequence.
2(8Y8) must be distributed. To distribute we multiply the outside number (2) by the inside numbers (8Y8).
(2x8Y) + (2x8)
16Y  16 is our result.
Hope this helps!