Mathematics

Question

Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?

1 Answer

  • The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.

    Ways of having 17:

    Die 1     Die 2     Die 3    sum
    6            6            5          6+6+5 = 17
    6            5            6          6+5+6 = 17
    5            6            6          5+6+6 = 17

    Those are the only 3 possibilities of having 17 (you can only loose 1 point).

    The total number of outcomes are 6*6*6 = 216

    So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139 
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