Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)
Question
2 Answer

1. User Answers tt625153
Answer:10 square units.
Stepbystep explanation:
There are three vertices in this triangle: \rm A, \rm B, and \rm C. The three sides are \rm AB, \rm BC, and \rm AC.
Among the two endpoints of altitude \rm CD, only \rm C is a vertex of this triangle. Hence, \rm AB, the side opposite to vertex \rm C\!, would be the base of this altitude.
Apply the Pythagorean Theorem to find the length of \rm AB (the base) and \rm CD (the height).
By the Pythagorean Theorem, the distance between points (x_0,\, y_0) and (x_1,\, y_1) is \sqrt{(x_1  x_0)^{2} + (y_1  y_0)^{2}}.
The distance between \rm C (2,\, 0) and \rm D (4,\, 2) is:
\sqrt{(4  2)^{2} + (2  0)^{2}} = \sqrt{8} = 2\, \sqrt{2}.
Hence, the length of altitude \rm CD would be 2\sqrt{2} units.
Similarly, the length of side \rm AB would be:
\sqrt{(6  1)^{2} + (0  5)^{2}} = \sqrt{50} = 5\, \sqrt{2}.

2. User Answers jeterlawncare
Answer:
10 square units
Stepbystep explanation:
Hope this helps :)